Can you me plz in number 12,13,and 14 find the sum or difference. write your answer in simplest form plz explain good so i understand

12. 11/18-1/6=4/9

13. 2/7+2/5=24/35

14. 3/4-3/10=9/20

Step-by-step explanation:

12. 11/18-1/6

11/18-1/6=11/18-(1/6)*(3/3)

11/18-1/6=11/18-(1*3)/(6*3)

11/18-1/6=11/18-3/18

11/18-1/6=(11-3)/18

11/18-1/6=8/18

Dividing the numerator and denominator of the fraction on the right side of the equation by 2:

11/18-1/6=(8/2)/(18/2)

11/18-1/6=4/9

13. 2/7+2/5

2/7+2/5=(2/7)*(5/5)+(2/5)*(7/7)

2/7+2/5=(2*5)/(7*5)+(2*7)/(5*7)

2/7+2/5=10/35+14/35

2/7+2/5=(10+14)/35

2/7+2/5=24/35

14. 3/4-3/10

3/4-3/10=(3/4)*(5/5)-(3/10)*(2/2)

3/4-3/10=(3*5)/(4*5)-(3*2)/(10*2)

3/4-3/10=15/20-6/20

3/4-3/10=(15-6)/20

3/4-3/10=9/20

4/9, 24/35, 9/20

Step-by-step explanation:

Question #12: 11/18 - 1/6

Given denominators are 18 and 6, their least common multiple would be 18.

So common denominator is 18, and we need to make 18 below each.

First fraction is 11/18.

Second fraction is 1/6 which would be (1x3)/(6x3) = 3/18.

Now, 11/18 - 1/6 = 11/18 - 3/18 = (11-3)/18 = 8/18 = 4/9.

Hence, 4/9 is the simplified answer of problem #12.

Question #13: 2/7 + 2/5

Given denominators are 7 and 5, their least common multiple would be 35.

So common denominator is 35, and we need to make 35 below each.

First fraction is 2/7 which would be (2x5)/(7x5) = 10/35.

Second fraction is 2/5 which would be (2x7)/(5x7) = 14/35.

Now, 2/7 + 2/5 = 10/35 + 14/35 = (10+14)/35 = 24/35.

Hence, 24/35 is the simplified answer of problem #13.

Question #14: 3/4 - 3/10

Given denominators are 4 and 10, their least common multiple would be 20.

So common denominator is 20, and we need to make 20 below each.

First fraction is 3/4 which would be (3x5/4x5) = 15/20.

Second fraction is 3/10 which would be (3x2)/(10x2) = 6/20.

Now, 3/4 - 3/10 = 15/20 - 6/20 = (15-6)/20 = 9/20.

Hence, 9/20 is the simplified answer of problem #14.

won't that be plagrisim thought?

step-by-step explanation:

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58