Find the vertex of this parabola y=-5x^2-10x-15

vertex = (- 1, - 10 )

Step-by-step explanation:

given the equation of a parabola in standard form

y = ax² + bx + c : a ≠ 0

Then the x-coordinate of the vertex is

= -

y = - 5x² - 10x - 15 is in standard form

with a = - 5, b = - 10 and c = - 15, hence

= - = - 1

substitute x = - 1 into the equation for y

y = - 5(- 1)² - 10(- 1) - 15 = - 5 + 10 - 15 = - 10

vertex = (- 1, - 10 )

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this