Arectangle shed is fenced with 120ft long barbed wire. if length of the shed is twice as long as the width, that is the length?

40 ft  

Step-by-step explanation:

Data:

(1) P = 120 ft

(2) l = 2w

Calculations:

(3)  P = 2l + 2w           Substitute (1) and (2) into (3)

  120 = 2(2w) + 2w     Multiply

  120 = 4w +2w           Combine like terms

  120 = 6w                   Divide by 6

(4) w = 20 ft                Substitute (4) into (2)

      l = 2 × 20

      l = 40 ft

Check:

120 = 2×40 + 2×20

120 = 80 + 40

120 = 120

step-by-step explanation:

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,