What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation is y=−2/3x+5 ? enter your answer in the box.

y = x - 11

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = - x + 5 is in this form

with m = -

given a line with slope m then the slope of a line perpendicular to it is

= - = - = , hence

y = x + c ← is the partial equation

to find c substitute (8, 1) into the partial equation

1 = 12 + c ⇒ c = 1 - 12 = - 11

y = x - 11 ← equation of line

Step-by-step explanation:

We have to find the equation a line which passes through the point (8, 1) and is perpendicular to a line with the equation .

So the slope for this equation will be the negative reciprocal of the line which is perpendicular to it i.e. .

Finding the y-intercept of the line:

Therefore, the equation of the line will be .

the radius is 2 times the diameter.

step-by-step explanation: