The cost of (x-5)apples is rs.(x^2 -9x +20).what is the cost of one apple.

The cost of one apple from the equation is (x-4).

From the question, we have that the cost of (x-5)apples is Rs.(x^2 -9x +20). We are to get the cost of 1 apple.

The cost of one apple is given as:

Hence the cost of one apple from the equation is (x-4).

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x - 4

Step-by-step explanation:

divide the cost of (x - 5) apples by x - 5, that is

= ← factor numerator

cancel the factor (x - 5) on numerator/denominator

cost of 1 apple = x - 4

idk sry

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.