Given: bisects rts r = s prove: 1. segment tq bisects ∠rts; ∠r = ∠s definition of perpendicular. 2. ∠1 = ∠2 definition of angle bisector. 3. tq = tq aas 4. triangle rtq congruent to triangle stq given 5. ∠3 = ∠4 cpcte 6. segment tq ⊥ segment rs reflexive

Solution:

Given : T Q bisects ∠RT S. And , ∠R=∠S

To Prove : T Q ⊥ R S

Proof : In Δ R T Q and Δ ST Q

T Q bisects ∠ R T S.

So, ∠1=∠2  →→→→    [Definition of angle bisector.]

T Q is Common.

∠R =∠S→→[Given]

Δ R T Q ≅ ST Q→→[AS A]

∵ ∠3 = ∠4  →→→[C P C T E]

But ∠3 and  ∠4 forms Linear pair.

∠3 + ∠4 = 180°

2 ∠3 = 180°

∠3 = 90°

∠3 = ∠4 =90°

So, Segment T Q ⊥ Segment RS.

Hence proved.

the largest number of the four options is 1.8 x 10-2

you have it in scientific notation.

1.80 x 10-6   = 0.00000180

1.80 x 10-4   = 0.000180 (bigger, or "less small", than the former one)

so

1.8 x 10-2       = 0.0180. as you see. the "less small", or the biggest one of them all.

as you have negative exponent, it means you are dividing 1.8 by 100 (i.e. moving the dot towards left, two times).

if you had positive exponent for the scientific notation, power of tenths, you would be multiplying times 100 (moving the dot towards right) as below:

1.8 x (10)2 = 180

so. if you have negative exponent in scientific notation, move the dot toward left. if it is positive, toward right as many times the exponent tells you.