The axis of symmetry for the function f(x)=-x2-10+16 is x=-5. what are the coordinates of the vertex of the graph?

(-5,41)

Step-by-step explanation:

The axis of symmetry is the x coordinate for the vertex. so, x= -5. Now plug that into the equation:

-(-5)^2 - 10(-5) + 16 ***I'm assuming it is 10x though it says just 10

-25+50+16= 41

The vertex is at (-5,41)

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value

step-by-step explanation: it is d