Using a pair of dice, what is the probability of throwing a sum of nice twice in a row?

1/16

Step-by-step explanation:

    +      Dice2      

Dice1   1         2         3         4         5          6

1            2        3         4         5         6           7

2            3        4         5        6         7           8

3            4         5        6        7         8           9

4            5         6         7        8       9            10

5            6         7         8        9      10          11

6            7         8         9       10       11          12

Probability = number of desired outcome / total number of outcome

                  =  4 / 36

                  =  1/9

The probability of rolling a 9 the first time is therefore  = 1/4

The probability of rolling a 9 twice in a row is just the product of the probability for two independent rolls each producing a 9.

That is, 1/4 * 1/4 = 1/16 = 0.0625.

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hope this you and

step-by-step explanation: