Use substitution to solve the linear system of equations. y=4x3x+5y=-46(-8, -2)(8, -2)(-2, 8)(-2, -8)

(- 2, - 8 )

Step-by-step explanation:

given the 2 equations

y = 4x → (1)

3x + 5y = - 46 → (2)

Substitute y = 4x into (2)

3x + 5(4x) = - 46

3x + 20x = - 46

23x = - 46 ( divide both sides by 23 )

x = - 2

substitute x = - 2 into (1)

y = 4 × - 2 = - 8

solution (- 2, - 8 )

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step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)