Solve y= for x.

x = sqrt((2 y)/5 - 31/100) + 3/10 or x = 3/10 - sqrt((2 y)/5 - 31/100)

Step-by-step explanation by completing the square:

Solve for x:

y = 1/2 x (5 x - 3) + 1

y = 1/2 x (5 x - 3) + 1 is equivalent to 1/2 x (5 x - 3) + 1 = y:

1/2 x (5 x - 3) + 1 = y

Expand out terms of the left hand side:

(5 x^2)/2 - (3 x)/2 + 1 = y

Multiply both sides by 2/5:

x^2 - (3 x)/5 + 2/5 = (2 y)/5

Subtract 2/5 from both sides:

x^2 - (3 x)/5 = (2 y)/5 - 2/5

Add 9/100 to both sides:

x^2 - (3 x)/5 + 9/100 = (2 y)/5 - 31/100

Write the left hand side as a square:

(x - 3/10)^2 = (2 y)/5 - 31/100

Take the square root of both sides:

x - 3/10 = sqrt((2 y)/5 - 31/100) or x - 3/10 = -sqrt((2 y)/5 - 31/100)

Add 3/10 to both sides:

x = sqrt((2 y)/5 - 31/100) + 3/10 or x - 3/10 = -sqrt((2 y)/5 - 31/100)

Add 3/10 to both sides:

 x = sqrt((2 y)/5 - 31/100) + 3/10 or x = 3/10 - sqrt((2 y)/5 - 31/100)

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.

correct answer is option b.

step-by-step explanation:

the true statement about geometric figure is option b that is one line can be drawn through all three points.

if three points are on the same plane, they can be connected by a line.