Polygon abcde has the vertices a(2, 8), b(4, 12), c(10, 12), d(8, 8), and e(6, 6). polygon mnopq has the vertices m(-2, 8), n(-4, 12), o(-10, 12), p(-8, 8), and q(-6, 6). a transformation or sequence of transformations that can be performed on polygon abcde to show that it is congruent to polygon mnopq is a . if polygon mnopq is translated 3 units right and 5 units down, it will coincide with a congruent polygon, vwxyz, with its vertices at .

A transformation or sequence of transformations that can be performed on polygon ABCDE to show that it is congruent to polygon MNOPQ is a:

Reflection across the y-axis

Step-by-step explanation:

Please, see the attached graph.

The polygon ABCDE is on the right side, first (I) quadrant.

The polygon MNOPQ is on the left side, second (II) quadrant.

We can see that the polygon MNOPQ is a reflection of the polygon ABCDE across the y-axis (only the abscissas change their signs from positive to negative) .

last part is

v(1, 3)

w(-1, 7)

x(-7, 7)

y(-5, 3)

z(-3, 1)

what he has is correct he just forgot about the last part

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.