Dorthy purchased a used that depreciate under a straight line method. the initial value of the car 8400 and the salvage value is 400 if the car is expected to have a useful life for another 5 years how much would it depreciate each year? ( answer quickly)a. 2000.00b. 1600.00c. 80.00d. 400.00

B. 1600.00

It would depreciate 1600 per year

Step-by-step explanation:

Since,

Dorthy purchased a used that depreciate under a straight line method

so, we can use linear equation formula

We are given

initial value of car  is 8400

so,

we can use slope-intercept form of line

now, we can plug value

the salvage value is 400 if the car is expected to have a useful life for another 5 years

so, at x=5 , y=400

we can plug it and solve for m

So,

It would depreciate 1600 per year

x = 12

y = 15

step-by-step explanation:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0