What is a polynomial function in standard form with zeros 1, 2, -3, and -1? g(x)=x^4+x^3-7x^2-x+6 g(x)=x^4+x^3+7x^2-x+6 g(x)=x^4+x^3-7x^2-x-6 g(x)=x^4-x^3-7x^2-x+6

[tex] g(x)=x^4+x^3-7x^2-x+6[\tex]

Step-by-step explanation:

Since, According to the question,

1, 2, - 3 and - 1 are zeros of the function g(x),

Also, function has the degree 4.

Thus, [tex]g(x) = (x-1)(x-2)(x+3)(x+1)[\tex]

[tex] g(x) = (x-1)(x-2)(x^2+4x+3)[\tex]

[tex] g(x) =(x-1)(x^3+4x^2+3x-2x^2-8x-6)[\tex]

[tex] g(x) =(x-1)(x^3+2x^2-5x-6)[\tex]

[tex] g(x) = x^4+x^3-7x^2-x+6[\tex]

it would be:

c.parallelogram.

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.