Three consecutive integers have a sum of –21. which equation can be used to find the value of the three numbers? a. x+x+x= -21 b. x+2x+3x= -21 c. x+(x+1)+(x+2)= -21 d. x+(x+2)+(x+4)= -21

c. x+(x+1)+(x+2)= -21

Step-by-step explanation:

Consecutive integers are in a row, like 1,2,3

Let x =the first integer

The next integer is 1 ahead of it

x+1  = next integer

Add 1 to move to the 3rd integer

x+1+1 = x+2

x+2 = the 3rd integer

Add the 3 integers

x+(x+1)+(x+2) = -21

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

believe it or not anna is correct good job anna give me a fist bump there u go gal