An old bone contains 80% of its original carbon-14. use the half-life model to find the age of the bone. find an equation equivalent. how old is the bone

Part 1 = C. (the LAST one)  /// Part 2 = 0.8 Part 3 = B. (about 1,845 years)

Step-by-step explanation:

theyre all correct.

An old bone contains 80% of its original carbon-14 in 1844.6479 years

Step-by-step explanation:

We know that

half life time of C-14 is 5730 years

so, h=5730

now, we can use formula

we can plug back h

and we get

An old bone contains 80% of its original carbon-14

so,

P(t)=0.80Po

we can plug it and then we solve for t

So,

An old bone contains 80% of its original carbon-14 in 1844.6479 years

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step-by-step explanation:

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step-by-step explanation: