What is the vertex of g(x) = |x−2|+1 ? (-2, 1) (2, 1) (2, -1) (-2, 1)

(2, 1)

Step-by-step explanation:

The absolute value equation has the form f(x) = a |x-h|+k where (h, k) is the vertex.

Since this is g(x)=|x-2|+1 then the vertex is (2,1).

Hello there,

What is the vertex of g(x) = |x−2|+1 ?

(-2, 1)

(2, 1)

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!