You measure the boiling point of water to be 98.5°c, 99.3 °c, and 99.8°c. the true boiling point is 100°c. what is your percent error, based on your average measurements? type your answer as a percentage, rounded to the nearest tenths place.

The percent error based on the average measurements is 0.8%.

Step-by-step explanation:

The standard equation for percent error is [(original - actual)/original} x 100.  The original amount is 100 degrees celcius.  Your average measurement can be found by adding the three temperatures together and dividing by the number of temperatures collected:  98.5 + 99.3 + 99.8 = 297.63/3 = 99.2.  When we place our numbers into the equation and solve, we get:  (100 - 99.2)/100 = 0.008 x 100 (to get our percentage) = 0.8%.

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft