The inequality x2 − 9 x2 + 6x + 8 > 0 can be factored as: (x + 3)(x - 3) (x + 4)(x + 2) > 0 use the critical points to determine the test regions. which are possible test points? –5 –4 –3.5 –3 –2.5 –2 0 5

The answers are:

-5

-3.5

-2.5

0

5

Step-by-step explanation:

The possible test points are -5,-3.5 , -2.5,0,5      

Step-by-step explanation:

Given : The inequality can be factored as

(x + 3)(x - 3) (x + 4)(x + 2) > 0

To find : Which are possible test points?

Solution : The inequality factored as

The critical points are defined as when we equation the factor to zero then the value of x is the critical point.

So, x+3=0 ⇒ x=-3

x-3=0 ⇒ x=3

x+4=0 ⇒ x=-4

x+2=0 ⇒ x=-2

The critical points of the given inequality are -4,-3,-2,3

The possible test points are the points except critical points.

Therefore, Out of the given options

The possible test points are -5,-3.5 , -2.5,0,5 as they are not critical points.

dont trust me im no expert these losers made me fail a test bro this sucks

step-by-step explanation:

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: