Asequence is defined by the function f(n)=f(n-1)+5. where n represents the number of the term for n> 1 and f(1)=-4. what are the first four terms of the sequence

The first four terms of the above sequence are 1, 6, 11, 16.

Step-by-step explanation:

A sequence is defined by the function f(n)=f(n-1)+5.

Where n represents the number of the term for n>1

First Put n = 2

f(2)=f(2-1)+5.

    = f (1) + 5

    = -4 + 5

    = 1

Second Put n = 3

f(3)=f(3-1)+5.

    = f (2) + 5

    = 1 + 5

    = 6

Third Put n = 4

f(4)=f(4-1)+5.

    = f (3) + 5

    =  6+ 5

    = 11

Second Put n = 5

f(5)=f(5-1)+5.

    = f (4) + 5

    = 11 + 5

    = 16

Therefore the first four terms of the above sequence are 1, 6, 11, 16.

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms

1; 35 is the ratio

step-by-step explanation: