How tall is a building that casts a 66-ft shadow when the angle of elevation of the sun is 29°?

36.58° ft

Step-by-step explanation

To solve this, you need to consider the complete visual as a triangle.

(Refer to the attached picture for better understanding)

We are assuming that the building  stands at an angle of 90° to the ground, making the triangle a right-angled triangle. We can apply the trignometric formula that links an angle to two sides: perpendicular, which is the height of the building (a) in this case, and base, the length of the shadow cast (b) by the building of known length.

tan(θ) = length of perpendicular (a) / length of base (b)

We are using this formula, as we know the values of the above mentioned sides of the triangle.

Solve:

tan(29°) = P / 66

0.554 x 66 = P

36.58 = P

answer: a rhombus has two lines of symmetry that run through one vertex to the one directly across it. unlike a square, planes through the center of each edge of a rhombus do not yield mirrored sides.

step-by-step explanation:

y + 11 = (1/4)(x + 16)

step-by-step explanation: