If x+y is 4 and x×y is 12 than what is x and y

Hello from MrBillDoesMath!

(x,y) = (2 - 2 i sqrt(2), 2 + 2sqrt(2))

(x,y) = (2 + 2 i sqrt(2), 2 - 2sqrt(2))

Discussion:

x + y = 4 => y = 4 - x

Substituting the y value in xy = 12 gives

xy = x(4-x) = 12 =>

4x - x^2 = 12 =>

x^2 -4x + 12 = 0 =>          (applying the quadratic formula)

x = 2 - 2 i sqrt(2)          ( y = 4 - x = 4 - (2 -2isqrt(2) )

and

x = 2 + 2 i sqrt(2)        ( y = 4 - x = 4 - (2 +2isqrt(2) )

Thank you,

MrB

(-1,-0.5)

step-by-step explanation: