Mary had flowers, of which 3/5 were roses and the rest were orchids. she sold 1/2 of the roses and 1/4 of the orchids. she then had 54 roses and orchids left. how many flowers did she have at first?

Mary have 90 flowers

Step-by-step explanation:

Given that Mary had flowers, of which 3/5 were roses and the rest were orchids.

Let Mary had x flowers.

∴ Roses are=

and orchids are

Now, She sold 1/2 of the roses and 1/4 of the orchids. She then had 54 roses and orchids left.

Hence, total flowers i.e roses and orchids sold are

The flowers which left are

⇒⇒

Therefore, Mary have 90 flowers

13.33%

say 50 oranges, then 100 apples

80 are red, 20 are yellow

total fruit = 150

20chances out of 150 for yellow

20/150 = 13.33%

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3