Calculate s58 for the arithmetic sequence {an}= {(5/6(n+(1/3)} if you could show me the steps that would be great. i keep following the directions in the lesson and getting 8,613/3 but all i have to choose from for answers are 146/2 91/2 8,671/6 9,267/6

We need the first term. Replace n with 1 and simplify

a_n = (5/6)*(n+(1/3))

a_1 = (5/6)*(1+(1/3))

a_1 = (5/6)*( (3/3) + (1/3) )

a_1 = (5/6)*( 4/3 )

a_1 = (5*4)/(6*3)

a_1 = 20/18

a_1 = 10/9

Now we need the 58th term.

Repeat the steps done above, but now use n = 58

a_n = (5/6)*(n+(1/3))

a_58 = (5/6)*(58+(1/3))

a_58 = (5/6)*( (174/3) + (1/3) )

a_58 = (5/6)*( 175/3 )

a_58 = (5*175)/(6*3)

a_58 = 875/18

Next, add up the first and last terms of the sequence we want. So add up a_1 and a_58

a_1 + a_58 = (10/9) + (875/18)

a_1 + a_58 = (20/18) + (875/18)

a_1 + a_58 = (20+875)/18

a_1 + a_58 = 895/18

Multiply this result by n/2 where n = 58

n/2 = 58/2 = 29

(n/2)*(a_1+a_58) = 29*(895/18)

(n/2)*(a_1+a_58) = 25955/18

The answer I'm getting is 25955/18

Because this answer is not listed, I'm thinking there must be a typo somewhere. Please update the problem.

5x+2x=49

7x=49

x=7. 35 apples

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .