Simultaneous equations 3x + 2y= 13x + 2y= -1

{x = 7  , y = -4

Step-by-step explanation:

Solve the following system:

{3 x + 2 y = 13 | (equation 1)

{x + 2 y = -1 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:

{3 x + 2 y = 13 | (equation 1)

{0 x+(4 y)/3 = (-16)/3 | (equation 2)

Multiply equation 2 by 3/4:

{3 x + 2 y = 13 | (equation 1)

{0 x+y = -4 | (equation 2)

Subtract 2 × (equation 2) from equation 1:

{3 x+0 y = 21 | (equation 1)

{0 x+y = -4 | (equation 2)

Divide equation 1 by 3:

{x+0 y = 7 | (equation 1)

{0 x+y = -4 | (equation 2)

Collect results:

 {x = 7  , y = -4

sorry

step-by-step explanation:

sorry, but im pretty sure its a now that i look at it

so the possibilities of the measurement of the side of the triangle are either it is longest side or not the longest side

when it is the longest side

s < 25 + 35s < 60

if it is not the longest side

35 < 25 + s10 < sso 10 < s < 60so the perimeter70 < p < 130