Ihave been stuck on this question for a while. i need to find the area of the shaded region and round to the nearest tenth.

818.4 in²

The area of a circular sector is given by ...

... A = (1/2)r²·θ . . . . . θ in radians

The area of the isosceles triangle with apex angle 150° is given by ...

... A = (1/2)r²·sin(θ)

Then the area of the shaded segment is ...

... A = (1/2)r²·(θ - sin(θ))

... A = (1/2)·(27.8 in)²(5π/6 -sin(5π/6)) ≈ 818.4 in²

If you (erroneously) use 3.14 for π, you get 817.9 in². Some answer keys expect you to use that value, even though it does not have sufficient accuracy for this problem.

x=4

step-by-step explanation:

it has the same slope and a different y-intercept

hope this : )