In the graph of the inequality, x-2y≥4, which is a value for x on the boundary line and the x-axis? ? : )

(4, 0)

Step-by-step explanation:

The point is on the x-axis when its y-coordinate is 0. Putting that value into the inequality and solving the "equal to" case gives ...

... x -2·0 = 4

... x = 4

Then the point of interest is (x, y) = (4, 0).

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)