Suppose a triangle has three sides of length of 3 and 4 in that the angle between these two sides is 60°. what is the length of the third side of the triangle

3.61 in. to the nearest hundredth.

Step-by-step explanation:

You use the Cosine Rule to solve this.

a^2 = b^2 + c^2 - 2bc cos 60    where a is the third side.

Plugging in the given values:_

a^2  = 3^2 + 4^2 - 2*3*4* cos 60

=   9 + 16 - 24*0.5

=  13

a = √13

= 3.61

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: