Consider the function f(x)= (x+4)(x-2) what is the equation of the axis of symmetry

if we zero out f(x), namely make y = 0, we can get the roots or x-intercepts for this quadratic equation

now, the equation is in x-terms, meaning is a vertically opening parabola, so the axis of symmetry will be x = something, a vertical line.

well, we have two x-intercepts, one at -4 and another at 2, and the vertex is right half-way between those guys

-4------------(-1)------------2

so the vertex is at x=-1, namely the axis of symmetry is x = -1.

hello, never fear papaguy is here!

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step-by-step explanation: