Graph -3x^2+12y^2=84. what are the domain and range? i already know the domain is all real numbers and the range is {y|y≤-√7 or y≥√7} i just need to find out how you get to that.

Explanation:

Written in standard form, the hyperbola's equation is ...

... y^2/7 - x^2/28 = 1

Then the ends of the transverse axis are located at y = ±√7. The region between these values is excluded from the range of the relation.

The slope of the function is 0.5.

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!