The angle of elevation of the sun (the angle the rays of sunlight make with the flat ground) at 10: 00 a. m. is 29°. at that point, a tree’s shadow is 32 feet long. how tall is the tree?

Height of the tree is approx 17.74 feet.

Step-by-step explanation:

the angle of elevation of the sun at 10:00 a.m. is 29°.

Then measure of angle C = 29°

At that point, a tree’s shadow is 32 feet long.

Then BC=32

Now we need to find about how tall is the tree.

So we can use trigonometric formula of right triangle to find missing height (x) of side AB.

Hence height of the tree is approx 17.74 feet.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

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