In △abc, m∈ ac and n∈ bc . prove that mn ∥ ab , if: am/cm =bn/cn

See proof below

Step-by-step explanation:

1. Consider in triangles ABC and MNC the ratio

Since then

2. Consider in triangles ABC and MNC the ratio

Since then

3. You are given that

then

4. The previous statement gives you that triangles ABC and MNC are similar (they have two pairs of proportional sides and common angle C). Similar triangle have congruent corresponding angles. Hence,

First pair of angles form corresponding angles at lines MN and AB and transversal BC and second pair of angles form corresponding angles at lines MN and AB and transversal AC. Since corresponding angles are congruent, the lines AB and MN are parallel.

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

b

step-by-step explanation:

the word superfluous means unnecessary