Aldrin and jan are standing at the edge of a huge field. at 2: 00 p. m., aldrin begins to walk along a straight path at a speed of 3 km/h. two hours later, jan takes a straight path at a 608 angle to aldrin’s path, walking at 5 km/h. at what time the two friends be 13km apart?

After 2:29 hours both Aldrin and Jan will be 13 km apart from each other.

Time at that instant will be : 4:00 pm + 2.29 hours= 6:29 pm

Step-by-step explanation:

According to the figure:

Ab= c = 13 Km

AC = b = =5t Km

After two hours the distance covered by the Aldrin say till point D :

Since, we are interested in determining the time at which Aldrin and Jan both 13 Km apart. For that Aldrin Additional distance covered by the Aldrin from point D to B is :

CB= a = CD+DB= 6+3t

We will apply Laws of cosines:

On solving the the above equation by quadratic formula we get two values of 't'

1) t = 2.49 hours , 2) t = -2.80 hours

Since,time cannot be in negative so we will ignore the negative value of t

t = 2.49 = 2:29 hours ,(0.49 hour=0.49 × 60 min=29.4 min)

After 2.49 hours after the walking of Jan. Both Aldrin and Jan will be 13 km apart from each other.

Time at that instant will be : 4:00 pm + 2:29 hours= 6:29 hour

x=6 and x=3

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