Describe how the graph of y=x^2 would be shifted to produce a graph of y=2x^2+12x+3=0?

The graph shifts 3 units left and 15 down. It narrows by a factor of 2 and is right side up.

Step-by-step explanation:

There are two ways of doing this. You can graph it, or you can put it in the vertex form by completing the square.

A quick way of putting this into the vertex form is write the general equation

y = a(x - h)^2 + k

h= - b/2a = - 12/4 = - 3

So the equation in vertex form is

y = 2(x + 3)^2 - 15

Description

y = 2(x + 3)^2 - 15

shifts 3 units to the left and 15 units down. It also narrows by a factor of 2. Finally, it is right side up.

Graph

Since you have seen the graph before, there is not much more to add. It just shows what has been written above.

300

step-by-step explanation:

28-600w < 300

28-600w > 300

600-28w < 300

600-28w > 300

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2