How much does a length of aluminum expand if it is 1.2 meters long at 15 degrees c and heated to 65 degrees c

∆L = aL∆T)
a = 23 × 10^(-6) K^(-1)
L = 1.2 m
∆T = 65°C - 15°C = 50 °C = 323.15 K
∆L = 23 × 10^(-6) × 1.2 × 323.15 m
∆L = 8.91894 × 10^(-3) m

1. statement- ca is parallel to db and e is the midpoint of ad reason- given2. statement- reason- alternate interior angles3. statement- de is congruent to ae reason- definition of midpoint4. statement- triangle aec is congruent to triangle deb reason- asa (angle side angle)