An arithmetic sequence has a first term of 3 and a fifth term of 31. what is the second term?

10

Step-by-step explanation:

let's call the difference in each term d so the sequence would look like

3,(3+d),(3+2d),(3+3d),(3+4d)

notice how in this sequence that (3+4d) is the fifth term so it must equal 31

3+4d=31

4d=28

d=7

now plug this into the second term

(3+(7))

and we see that the second term is 10

yes

yes yes yes

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: