What is the area of a square with a diagonals of the length of 6?

Area = 18

Step-by-step explanation:

We know that a square has side lengths of s

We can use the Pythagorean theorem to find s

a^2 + b^2 = c^2

We know that the hypotenuse or c = the length of the diagonal or 6

Substituting in what we know

s^2 + s^2 = 6^2

2s^2 = 36

Divide each side by 2

2s^2/2 = 36/2

s^2 = 18

Take the square root of each side

sqrt(s^2) = sqrt(18)

We only have to take the positive square root since it is a length

s = sqrt(9) sqrt(2)

s= 3sqrt(2)

The side length of the square is 3sqrt(2)

To find the area, we multiply the side  by the side or s^2

s^2 =  (3sqrt(2))^2

From above

s^2 = 18

its a straight line parallel to the time axis

idk wbu

step-by-step explanation: