Jim needs to rent a car. a rental company charges $21.00 per day to rent a car and $0.10 driven. for every mile . he will travel 250 miles. he has $115.00 to spend. write an inequality that can be used to determine d, the maximum number of days that jim can re ays that jim can rent a car

21d +25 ≤ 115

Step-by-step explanation:

Jim's cost will be ...

... 21.00·d + 0.10·250 = 21d +25

He wants his cost not to exceed his budget, so ...

... 21d +25 ≤ 115

The solution is ...

... 21d ≤ 90 . . . . subtract 25

... d ≤ 90/21 ≈ 4.3

so Jim can rent the car a maximum of 4 days.

The inequality that can be used to express this scenario is

115 ≤  21*d+ 25

Given data

Charges = $21 per day

Cost per driven distance = $0.10

Distance he will travel = 250 miles

Amount her has to spend = $115

Let the maximum number of days Jim can rent a car with $115 be "m"

Hence

Total amount = 21*d+ 0.1*250

Substituting and Simplifying we have

115 ≤  21*d+ 25

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answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.