Factor x^3-4x^2-3x+18=0 given that 3 is a zero. a) (x+2)(x-3)^2=0 b) (x-2)(x-3)^2=0 c) (x-2)(x-3)(x+3)=0 d) (x+2)(x-\sqrt{3})(x+\sqrt{3})=0

B: (x + 2)(x - 3)^2

Step-by-step explanation:

This is only going to have 3 roots. One of them is (x - 3)

D does not look right. So let's solve it using synthetic division.

3 || 1    - 4      -3       18

            3       -3      -18

     1     -1       -6        0

So what you have is a quadratic

The answer is B

y + 11 = (1/4)(x + 16)

step-by-step explanation:

b because it contains 40% of the possible results from the random list.  

0,1,2,3 v 4,5,6,7,8,9  

4 integers to 6 integers  

40% success vs 60% fail

step-by-step explanation: