Here are the first four terms of a sequence. 1/2 4/3 9/4 16/5. find the nth term of this sequence.

n^2/(n+1)

Step-by-step explanation:

n=1

1^2/(1+1) = 1/2

n=2

2^2/(2+1) = 4/3

n=3

3^2/(3+1) = 9/4

n^2/(n + 1)

Step-by-step explanation:

The numerators are the squares of the sequence numbers 1^1  2^2  3^2

The denominators are the  sequence numbers + 1, so the nth term is

n^2/(n + 1).

y > 1/3x

y < = -x + 4

hope this : )

if you was gonna solve for a, a is a   < -12