Lucy and ethel’s favorite store was having a sale. lucy bought 10 shirts and 4 pairs of jeans and spent $280. sabrina bought 12 shirts and 5 pairs of jeans and spent $344. assuming that each shirt was the same price, and each pair of jeans was the same price, how much did each shirt and each pair of jeans cost? write a system of equations to represent this situation. then solve for the solution using the elimination method.

Each shirt costs 12 dollars.

Each pair of pants cost 40 dollars.

Step-by-step explanation:

Let x represent the shirts

Let y represent the pair of jeans

10x + 4y = $280

12x + 5y = $344

Use elimination method to eliminate y

• Multiply the entire first equation by 5.

• Multiply the second entire equation by -4.

5(10x +4y = $280)

-4(12x + 5y = $344)

50x + 20y = 1400

-48x -20y = -1376

2x = 24

x = 12

Each shirt costs 12 dollars.

Solve for how much each pair of jeans costs.

10(12) + 4y = 280

120 + 4y = 280

4y = 160

y = 40

the first one

step-by-step explanation:

just id the test.

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !