Find the range of values of x such that the quadratic function f(x)=(x+5)^2-16 is positive.

f(x)=(x−5)2−16

Set the polynomial equal to y

to find the properties of the parabola.

y=(x−5)2−16

Use the vertex form, y=a(x−h)2+k

, to determine the values of a, h, and k

.

a=1

h=5

k=−16

Since the value of a

is positive, the parabola opens up.

Opens Up

Find the vertex (h,k)

.

(5,−16)

Find p

, the distance from the vertex to the focus.

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14

Find the focus.

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(5,−634)

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

x=5

step-by-step explanation:

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.