Mathematics, 27.06.2019 07:00 tiffanibell71
Check this the work of a student to solve a set of equations is shown: equation a: y = 15 β 2z equation b: 2y = 3 β 4z step 1: β2(y) = β2(15 β 2z) [equation a is multiplied by β2.] 2y = 3 β 4z [equation b] step 2: β2y = 15 β 2z [equation a in step 1 is simplified.] 2y = 3 β 4z [equation b] step 3: 0 = 18 β 6z [equations in step 2 are added.] step 4: 6z = 18 step 5: z = 3 in which step did the student first make an error? step1 step 2 step 3 < < < < < step 4
Answers: 1
Mathematics, 21.06.2019 13:40
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Check this the work of a student to solve a set of equations is shown: equation a: y = 15 β 2z equ...
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