What is the r^2 value of the following data to three decimal

0.783

Step-by-step explanation:

To find first r and then r square for the data

correlation coefficient of x and y = Cov (x,y)/std dev x * std dev Y

Cov (x,y) = E(xy) -E(x)E(y)

Hence calculations would be as follows:

xyxy

122

21020

5525

718126

1025250

Mean51284.6

CovE(xy)-E(x)E(y)  24.6

r0.884640297

r^20.782588454

so answre is 0.783 after rounding off.

step-by-step explanation:

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)