An experiment consists of randomly selecting a marble from a bag, keeping it, and then selecting another marble. the bag contains 4 blue marbles, 3 green marbles, 7 red marbles, and 1 yellow marble. what is the probability of selecting a red marble and then a blue marble? show all work!

2/15

Step-by-step explanation:

How many marbles are in the bag

4blue + 3 green + 7 red + 1 yellow = 15 marbles

On the 1st draw:

 red/total  = 7/15

Since we keep the marble, there are only 14 marbles left

4blue + 3 green + 6 red + 1 yellow = 14

On the 2nd draw:

blue/total  = 4/14  = 2/7

To find the probability of the two draws, we multiply them together

1st draw * 2nd draw

7/15 * 2/7 = 2/15

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

answer: y = 3/2 x - 3

y = 1/8 x - 3/4 that would be your correct option

step-by-step explanation: w