What are the solutions to the equation x^4+3x^2+2=0?

i, -i , 2i, -2i

Step-by-step explanation:

We can factor this as follows:-

x^4 + 3x^2 + 2 = 0

(x^2 + 1)(x^2 + 2) = 0

By the zero product postulate:-

x^2 + 1 = 0 or x^2 + 2 = 0

x^2 + 1 = 0

x = +/- √-1 = i , -i

x^2 + 2 = 0

x = +/- √-2 =  2 √-1 , -2√-1 = 2i; -2i.

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )