Log 6 (1/36) 6 is the base. how to evaluate this?

We can write the argument of the logarithm as a power of 6:

Then using the property that , we get

and since , we have , so the value of this expression is simply -2.

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.