Plz i don't understand. and could you plz explain how to do it as well. at the end of 2007-2008 football seasons, 38 super bowl games had been played with the current two football leagues, the american football conference (afc) and the national football conference (nfc). the nfc won two more games than the afc. how many games did each conference win?

AFC won 18 times, NFC won 20 times

N = number of times an NFC team won the superbowl

A = number of times an AFC team won the superbowl

The two unknown numbers (N and A) must add to 38 as there are no other options (either there is an NFC or AFC champion) so N+A = 38

The other equation is N = A+2 because "the NCF won two more games than the AFC"

We can replace the "N" in N+A = 38 with A+2 because N = A+2, meaning that N and A+2 are the same

So,

N+A = 38

A+2+A = 38  ... replace N with A+2; solve for A

2A+2 = 38

2A+2-2 = 38-2

2A = 36

2A/2 = 36/2

A = 18

The AFC won 18 times. Use this value of A to find N

N = A+2

N = 18+2

N = 20

The NFC won 20 times.

As a check, adding up the two counts should get us 38

N+A = 38

20+18 = 38

38 = 38

Answer is confirmed

answer: 91

step-by-step explanation:

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8