In a rectangle, the ratio of the length to the width is 5 : 2. the length of the rectangle is 13.875 feet greater than the width. what are the perimeter and the area of the rectangle?

Since the ratio of the length to the width is 5 : 2, let's call the length 5x and the width 2x.
If the length is 13.875 feet longer than the width, then length=13.875+width.

Substituting 5x for length and 2x for width:
5x=13.875+2x
Combine like terms by subtracting 2x from both sides:
3x=13.875 (feet)
Divide both sides by 3:
X=4.625 feet

We can solve for the perimeter even without plugging in x to find the length and width; just use the expressions 5x for length and 2x for width.

Perimeter = length + length + width + width = 5x + 5x + 2x + 2x = 14x = 14 * 4.625 =
64.75 feet

Area = length * width = (5x)(2x) = 10x^2 = 10 * (4.625)^2 = 21.004225 square feet (I solved that by typing it out on here, might wanna recheck with a calculator).

Make sure to include the right units. Hope that helped! :)

The principal, real, root of: 50−−√2=7.071067817.07106781−7.0710678150 is not a perfect square