Identify an equation in point-slope form for the line parallel to y=5x+2 that passes through (-6,-1)

y = 5x + 29

Step-by-step explanation:

y=5x+2

Given equation is in the form of y=mx+b

Where m is the slope = 5

and b is the y intercept = 2

When the lines are parallel then their slopes are equal

So the slope of parallel line is also 5 (m=5)

Given that the line passes through (-6,-1)

We use point slope formula

y-y1= m (x-x1)

m=5, x1= -6, y1=-1

Plug in all the values

y - (-1) = 5(x-(-6))

y + 1= 5 (x+6)

y + 1= 5x + 30

Subtract 1 on both sides

y = 5x + 29

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)