What is the solution set to the following system x+y=5 x^2+y^2=25 a (0, -5) (-5,0) b (0,5) (-5,0) c (0,-5) (5, 0) d (0, 5) (5,0)

D (0, 5), (5, 0)

Anything with -5 and 0 will not satisfy x+y=5. This eliminates the first three choices.

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It is easiest to check the offered answers. You can also solve this graphically, or by solving the simultaneous equations.

You can, for example, square the first equation and subtract the second:

... (x+y)² -(x²+y²) = 5² -25

... 2xy = 0

This will be true for x=0 or for y=0, so (0, 5) and (5, 0) are solutions to the pair of equations.

mx+89b(-98)nb

step-by-step explanation: